4y^2+(2/3)y^2=96

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Solution for 4y^2+(2/3)y^2=96 equation: 


y in (-oo:+oo)

4*y^2+(2/3)*y^2 = 96 // - 96

4*y^2+(2/3)*y^2-96 = 0

14/3*y^2 = 96 // : 14/3

y^2 = 144/7

y^2 = 144/7 // ^ 1/2

abs(y) = (144/7)^(1/2)

y = (144/7)^(1/2) or y = -(144/7)^(1/2)

y in { (144/7)^(1/2), -(144/7)^(1/2) }

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